Date: Jun 17, 2013 1:49 PM
Author: Nasser Abbasi
Subject: Re: The Charlwood Fifty

On 6/17/2013 11:11 AM, wrote:
> Apart from the compactness of antiderivatives, as measured by leaf
> counting, continuity on the real axis and absence of complex
> intermediate results when evaluated on the real axis (which implies
> absence of the imaginary unit) are important in my view, and usually
> take precedence over compactness.
> Thus, my 45-leafed result is fully continuous along the real axis,
> whereas the shorter ATAN alternative:
> INT(COS(x)^2/SQRT(COS(x)^4 + COS(x)^2 + 1), x) =
> = - 1/3*ATAN(COT(x)*COS(x)^2/SQRT(COS(x)^4 + COS(x)^2 + 1))
> as well as Albert's 37-leafed ASIN version:
> INT(COS(x)^2/SQRT(COS(x)^4 + COS(x)^2 + 1), x) =
> = - ASIN(COS(x)^3)*SQRT(1 - COS(x)^6)*CSC(x)
> /(3*SQRT(1 + COS(x)^2 + COS(x)^4))
> jump at x = -pi, 0, pi, etc. This constitutes an unnecessary obstacle in
> definite integration - imagine some quantity integrated along the path
> of an orbiting spacecraft.

I noticed that last night when I made a plot of them to compare. Here is
the plot

I might add a link then next to each given optimal entry in
the table showing a plot of the antiderivate, will be easy to add.

> I usually accept logarithmic evaluations like INT(1/x, x) = LN(x), which
> can be complex where the integrand is real (here for x < 0). I think
> that users (e.g. calculus students) who need this integral from x = -2
> to x = -1, say, should be able to accept that constants involving some
> formal quantity #i appear which drop out of the final result.
> Martin.

Thanks for the information, this helped.

On a related point, would you please help me understand how
free version of reduce transformed



arcsin( sin(g0) ) * cos(g0) * log( sin(g0) )

by replacing x with sin(g0).

i.e Where does cos(g0) term come from in the above transformation?

Here is a link to the reduce trace for integral #1, which it
could not do btw. And the above was the first step in the process.