Date: Sep 21, 2013 12:26 PM
Author: HOPEINCHRIST
Subject: PROOF OF 1:3 PUBLISHED TODAY

International Journal of Applied Mathematical Research, 2 (4) (2013) 452-454
┬ęScience Publishing Corporation
www.sciencepubco.com/index.php/IJAMR
Pythagoras 1:3, an expression of the finite universe of mathematics
Vinoo Cameron
Hope research, Athens, Wisconsin, USA
*Corresponding author E-mail: frontier.com
Abstract
The author has published several papers which are may be hard to understand and stand as a testament to the discovery
of 1:3 mathematics which is an absolute accommodation of numbers, prime numbers placement , and precise angles.
The author has published a continuous Prime sieve at the divergence of (5/6, 1/6) and (1/3 and 2/3), a final attempt is
made here to communicate the simple mathematics of the finite universe of mathematics to the dead current
mathematics, that in the authors opinion is dead to the absolute reality of mathematics, as a form of approximate
mathematics and has offered this manuscript for review at any mathematical venue. This discussion is about 1:3
Pythagoras (?1+?9=?10 hypotenuse) and points to the clear mathematical relationship between 19 and 3^2. The span of
the divergence at 1:3 is clearly2+ 1/ (3^2) from the base of 2. Current mathematics is currently operating in the
approximation of their myriad current theory, and they seem content.
Keywords: Pythagorean 1:3, configuration of 1(5/6, 1/6:1/3, 2/3), Arabic numerical (1^2-3^2).
1 Introduction
This is expressed by the ten published papers referenced below, the divergence of this angle is in the configuration of a
cone in two planes, one of these planes is represented by the 1/3 + 2/3=1, and the other plane is represented by 1/6
+5/6.=1 As shown previously the 1:3 divergences accommodates the numbers naturally, and the equalization of
numbers is at 4:12(1:3) as shown in the last paper on end calculus. 5+11+17=9+11+13 (17-5=12; 13-9=4)
2 Mathematics
The Arabic numerical define numerals from 1^2-3^2(1-9). Pythagoras at 1:3 represents the squared expression of the
Arabic numerals (1^2+3^2) =? (10).
There is not much explaining to be done here here as the author does not feel obliged to explain the simplicity of his
work any further for a mathematics that excels at approximations (whole numbers are absolute).
3^2=9, a square with sides of 3 each
Reciprocal Value = 1/ (3^2) =0.111111111111.
Now in applying the Pythagoras theorem to the square, a linear advancement of 3 is in one plane, followed by ascension
of 1 in the perpendicular plane, which yields a diagonal hypotenuse of ? (10).
1 19
2. 2. 1 : 3
2
3 1
9
n
n
? ? ? ?
?
? ?
?? ??
[? (10)]^2-[? (9)] ^2=1
10^2-9^2=19
19/19=1
(