Date: Sep 21, 2013 12:26 PM Author: HOPEINCHRIST Subject: PROOF OF 1:3 PUBLISHED TODAY International Journal of Applied Mathematical Research, 2 (4) (2013) 452-454

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Pythagoras 1:3, an expression of the finite universe of mathematics

Vinoo Cameron

Hope research, Athens, Wisconsin, USA

*Corresponding author E-mail: frontier.com

Abstract

The author has published several papers which are may be hard to understand and stand as a testament to the discovery

of 1:3 mathematics which is an absolute accommodation of numbers, prime numbers placement , and precise angles.

The author has published a continuous Prime sieve at the divergence of (5/6, 1/6) and (1/3 and 2/3), a final attempt is

made here to communicate the simple mathematics of the finite universe of mathematics to the dead current

mathematics, that in the authors opinion is dead to the absolute reality of mathematics, as a form of approximate

mathematics and has offered this manuscript for review at any mathematical venue. This discussion is about 1:3

Pythagoras (?1+?9=?10 hypotenuse) and points to the clear mathematical relationship between 19 and 3^2. The span of

the divergence at 1:3 is clearly2+ 1/ (3^2) from the base of 2. Current mathematics is currently operating in the

approximation of their myriad current theory, and they seem content.

Keywords: Pythagorean 1:3, configuration of 1(5/6, 1/6:1/3, 2/3), Arabic numerical (1^2-3^2).

1 Introduction

This is expressed by the ten published papers referenced below, the divergence of this angle is in the configuration of a

cone in two planes, one of these planes is represented by the 1/3 + 2/3=1, and the other plane is represented by 1/6

+5/6.=1 As shown previously the 1:3 divergences accommodates the numbers naturally, and the equalization of

numbers is at 4:12(1:3) as shown in the last paper on end calculus. 5+11+17=9+11+13 (17-5=12; 13-9=4)

2 Mathematics

The Arabic numerical define numerals from 1^2-3^2(1-9). Pythagoras at 1:3 represents the squared expression of the

Arabic numerals (1^2+3^2) =? (10).

There is not much explaining to be done here here as the author does not feel obliged to explain the simplicity of his

work any further for a mathematics that excels at approximations (whole numbers are absolute).

3^2=9, a square with sides of 3 each

Reciprocal Value = 1/ (3^2) =0.111111111111.

Now in applying the Pythagoras theorem to the square, a linear advancement of 3 is in one plane, followed by ascension

of 1 in the perpendicular plane, which yields a diagonal hypotenuse of ? (10).

1 19

2. 2. 1 : 3

2

3 1

9

n

n

? ? ? ?

?

? ?

?? ??

[? (10)]^2-[? (9)] ^2=1

10^2-9^2=19

19/19=1

(