Date: Sep 28, 2013 12:30 PM
Author: Hetware
Subject: Is (t^2-9)/(t-3) defined at t=3?
I'm reading a 1953 edition of Thomas's Calculus and Analytic Geometry.

In it he states that given:

F(t) = (t^2-9)/(t-3)

F(t) = (t-3)(t+3)/(t-3) = t+3 when t!=3.

But F(t) is not defined at t=3 because it evaluates to 0/0.

If someone were to ask me if (t^2-9)/(t-3) is defined when t=3, I would

say it is because it can be simplified to t+3. Am I (and/or Thomas)

engaging in meaningless hair-splitting regarding the question of F(3)

being defined?