Date: Sep 30, 2013 3:46 PM
Author: LudovicoVan
Subject: Re: Is (t^2-9)/(t-3) defined at t=3?

"Virgil" <virgil@ligriv.com> wrote in message 
news:virgil-523099.13365230092013@BIGNEWS.USENETMONSTER.COM...
> In article <l2bb8m$3gt$1@dont-email.me>,
> Robin Chapman <R.J.Chapman@ex.ac.uk> wrote:

>> On 30/09/2013 07:58, Ciekaw wrote:
>> > On Saturday, September 28, 2013 6:30:42 PM UTC+2, Hetware wrote:
>> > >
>> >> But F(t) is not defined at t=3 because it evaluates to 0/0.

>> >
>> > Hint L'Hôpital's rule
>> >
>> > f(t)=t-3
>> > f'(t)=1
>> >
>> > lim[f(t)/f(t)]=lim[f'(t)/f'(t)]=lim[1/1]=1
>> >
>> > Analogy:
>> > If x=0 then sin(x)/x = 1

>>
>> Hetware: 0/0 = 3
>>
>> Ciekaw: 0/0 = 1
>>
>> Any more entrants?

>
> How about 0/0 = NAN ?


0/0 = |R, i.e. the entire real line, in closed interval arithmetic.

Julio