```Date: Oct 19, 2013 3:46 AM
Author: Sseziwa Mukasa
Subject: Re: Exercise of Programming with Mathematica

I can't determine a pattern that represents a pair which does not also match {{a,b},{c,d}}, but I can think of two options.  The first is not to use pattern matching at all, which may be more efficient anyway:In[5]:= {{a, b}, {c, d}, {e, f}}[[All, {2, 1}]]{{a, b}, {c, d}}[[All, {2, 1}]]Out[5]= {{b, a}, {d, c}, {f, e}}Out[6]= {{b, a}, {d, c}}The other is to limit the pattern matching to the appropriate level:In[21]:= Replace[{{a, b}, {c, d}, {e, f}}, {x_, y_} -> {y, x}, {1}]Replace[{{a, b}, {c, d}}, {x_, y_} -> {y, x}, {1}]Out[21]= {{b, a}, {d, c}, {f, e}}Out[22]= {{b, a}, {d, c}}Elegance as always is in the eye of the beholder,SseziwaOn Oct 18, 2013, at 4:45 AM, Zhenyi Zhang <infozyzhang@gmail.com> wrote:> Here is a rule designed to switch the order of each pair of expressions in a list. It works fine on the> first example, but fails on the second.> In[1]:= {{a, b}, {c, d}, {e, f}}/.{x_, y_} :> {y, x}> Out[1]= {{b, a}, {d, c}, {f, e}}> In[2]:= {{a, b}, {c, d}}/.{x_, y_} :> {y, x}> Out[2]= {{c, d}, {a, b}}> Explain what has gone wrong and rewrite this rule to correct the situation, that is, so that the second> example returns {{b, a}, {d, c}}>> My solution is the most stupid one.>> {{a, b}, {c, d}}/.{{x_, y_}, {w_, t_}} :> {{y, x}, {t, w}}>> May I ask any elegant solutions?>> Thanks.>
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