Date: Nov 1, 2013 10:02 AM
Author: Bart Goddard
Subject: Re: Formal proof of the ambiguity of 0^0
Dan Christensen <Dan_Christensen@sympatico.ca> wrote in news:13a5c4b5-
> Again, 0^0 is a natural number, but no value is assigned to it
And you don't see this as a problem? You don't realize
that (here) "assigning" and "defining" are synonyms?
You think that you didn't "wet your pants" just because
you call it "saving time"?
To be logical, you're going to have to choose between
the assertions: 1. 0^0 is undefined and 2. 0^0 has
a numerical value.
If you choose 1., then your proof is invalid because
your basis step doesn't hold. If you choose 2., then
you contradict your volumous rantings that 0^0 should
be left undefined.
Really, think this through.