```Date: Mar 28, 2014 3:18 AM
Author: Torsten
Subject: Re: Third order non-linear boundary value problem

"Rachel " <rachel-dore20@hotmail.com> wrote in message <lh1o34\$9lh\$1@newscl01ah.mathworks.com>...> Hey guys,> > I'm having a lot of trouble trying to get a numerical solution the the following boundary value problem,> > f'''+1/3ff''+1/3f'^2=0> > with the following boundary conditions,> > eta=0, f=0 & f''=0> eta=infintiy, f'=0> >  I am new to Matlab and I'm completely lost so your help would be much appreciated. I think this is how I set it up but I'm not sure??> >  function dfdeta = mat4ode(eta,f)>     dfdeta = [ f(2)>                f(3)>               -1/3*f(1)*f(3)-1/3*Y(2)*Y(2) ];> > and for the boundary conditions,> >   function res = mat4bc(ya,yb)> res = [  ya(3) >             ya(1)>            yb(2)];> > And this is an attempt at the rest the code,> > function mat4bvp(solver)> > if nargin < 1>   solver = 'bvp4c';> end    > bvpsolver = fcnchk(solver);> > infinity = 3;> > solinit = bvpinit(linspace(0,infinity,5),[0,0,0]);> > sol = bvpsolver(@mat4ode,@mat4bc,solinit);> > eta = sol.x;> f = sol.y;> > figure(1)> plot(eta,f)> legend('F_1', 'F_2', 'F_3', 3) > grid> > end> > I would be very grateful for the help. Thanks a mill.> > RachelThere is no need to use bvp4c for your boundary value problem.The solution is simply f=0.Best wishesTorsten.
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