http://mathforum.org/kb List of forum topics en http://mathforum.org/kb/thread.jspa?messageID=7928760&tstart=0#7928760 > lets assume a is a prime number and take it as 1.[/quote]
1 is NOT prime number so you objection is]]> Nov 27, 2012 10:19:48 AM Nov 27, 2012 10:19:48 AM GuyinMississippi 0 http://mathforum.org/kb/thread.jspa?messageID=7917498&tstart=0#7917498 Nov 4, 2012 1:04:18 AM Nov 4, 2012 1:05:34 AM Salahuddin559 0 http://mathforum.org/kb/thread.jspa?messageID=7917323&tstart=0#7917323 now 1 to the power 1 is same to 1.But if the number is more than 1 then your theory is]]> Nov 3, 2012 3:54:28 PM Nov 3, 2012 3:54:28 PM crunchcorn 2 http://mathforum.org/kb/thread.jspa?messageID=7242513&tstart=0#7242513 Dr. Cass:
Had forgotten that definition. Thanks!
Ben

> Date: Mon, 18 Oct 2010 09:56:32 -0400
>]]> Oct 18, 2010 6:58:52 PM Oct 18, 2010 6:58:52 PM benb 0 http://mathforum.org/kb/thread.jspa?messageID=7242102&tstart=0#7242102 > > Prove that a! E O(aa)
> >
> > p.s (aa) is suppose to be "a to the power of a"
Oct 18, 2010 9:57:20 AM Oct 18, 2010 9:57:20 AM dcass@sjfc.edu 0 http://mathforum.org/kb/thread.jspa?messageID=7242100&tstart=0#7242100 > Prove that a! E O(aa)
>
> p.s (aa) is suppose to be "a to the power of a"

Does this mean that]]> Oct 18, 2010 9:56:32 AM Oct 18, 2010 9:56:32 AM dcass@sjfc.edu 2 http://mathforum.org/kb/thread.jspa?messageID=7241034&tstart=0#7241034 ]]> Oct 16, 2010 10:23:27 PM Oct 16, 2010 10:23:27 PM izzy123 0 http://mathforum.org/kb/thread.jspa?messageID=7241032&tstart=0#7241032 Izzy,
Not to critique your notation, but what does "E O" mean? Thanks.
Ben

> Date: Sat, 16 Oct 2010]]> Oct 16, 2010 10:15:25 PM Oct 16, 2010 10:15:25 PM benb 1 http://mathforum.org/kb/thread.jspa?messageID=7241025&tstart=0#7241025
p.s (aa) is suppose to be "a to the power of a"
]]> Oct 16, 2010 10:10:11 PM Oct 16, 2010 10:10:11 PM izzy123 8