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List of forum topicsenRE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9203708&tstart=0#9203708
I just noticed something else: All posts to this point tacitly assume that "string" implies the adjective "uninterrupted." I]]>Aug 12, 2013 2:23:03 PMAug 12, 2013 2:23:03 PMbenb0Re: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9203696&tstart=0#9203696
> The same fish/rat logic (inclusion/exclusion) needs > to be applied to the second problem as well.]]>Aug 12, 2013 1:35:26 PMAug 12, 2013 1:35:26 PMPeter Scales1RE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9203689&tstart=0#9203689
Whoops! As students say, "My bad."

Will look over whatever I can find on this. This remains a great "hybrid" site,]]>Aug 12, 2013 12:40:51 PMAug 12, 2013 12:40:51 PMbenb0Re: RE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9203518&tstart=0#9203518
Aug 12, 2013 2:21:54 AMAug 12, 2013 2:21:54 AMmrickert1RE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9203306&tstart=0#9203306
Would like to comment, but I never received either of the original problems!

Thanks,

Ben

Aug 11, 2013 7:32:46 PMAug 11, 2013 7:32:46 PMbenb2Re: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=9202755&tstart=0#9202755
Aug 11, 2013 4:00:13 PMAug 11, 2013 4:00:13 PMmrickert5RE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=7826842&tstart=0#7826842
Dr. Scales: This site is serving as a de facto tutoring service for higher-level students who otherwise would be hard-pressed to get any]]>May 22, 2012 1:56:00 PMMay 22, 2012 1:56:00 PMbenb0Re: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=7825874&tstart=0#7825874
> Q1. How many permutations are there of the 26 letters > of the english alphabet that do not contain any of >]]>May 20, 2012 3:25:22 PMMay 20, 2012 3:25:22 PMPeter Scales7RE: Permutation problems
http://mathforum.org/kb/thread.jspa?messageID=7825630&tstart=0#7825630
Mahesh, Now I see how you get A, B and C. The latest post seems to point toward a solution. Thanks, Ben