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            <title>Re: integration by substitution</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=7834209&amp;tstart=0#7834209</link>

        

            <description><![CDATA[But anything with a square inside a square root cries out for a trig substitution.  Let x= sin(u) so that (1- x^2)^(1/2)= (1- sin^2(u))^(1/2)=]]></description>

        

            <jf:creationDate>Jun 7, 2012 7:53:19 AM</jf:creationDate>
            <jf:modificationDate>Jun 7, 2012 7:53:19 AM</jf:modificationDate>
            <jf:author>GEIvey</jf:author>
            <jf:replyCount>0</jf:replyCount>
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        <item>
            <title>Re: integration by substitution</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=7833597&amp;tstart=0#7833597</link>

        

            <description><![CDATA[You can separate x^3 into x^2(x) so your integral <br>int x^3(1- x^2)^(1/2)dx= int x^2(1- x^2)^(1/2)(xdx)<br><br>  Now let u= 1-x^2 so that du= -2xdx]]></description>

        

            <jf:creationDate>Jun 5, 2012 8:14:24 PM</jf:creationDate>
            <jf:modificationDate>Jun 5, 2012 8:14:24 PM</jf:modificationDate>
            <jf:author>GEIvey</jf:author>
            <jf:replyCount>1</jf:replyCount>
        </item>

        <item>
            <title>integration by substitution</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=7826063&amp;tstart=0#7826063</link>

        

            <description><![CDATA[integrate x^3*(1-x^2)^1/2<br><br>provide steps please<br><br>thank you<br>]]></description>

        

            <jf:creationDate>May 21, 2012 2:50:35 AM</jf:creationDate>
            <jf:modificationDate>May 21, 2012 2:50:35 AM</jf:modificationDate>
            <jf:author>yiwen00</jf:author>
            <jf:replyCount>2</jf:replyCount>
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