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        <title>Math Forum</title>
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        <item>
            <title>Re: Find  N(eps) so that   n^(1/n)  - 1  &amp;lt; eps  for n &amp;gt; N(eps)</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=7928363&amp;tstart=0#7928363</link>

        

            <description><![CDATA[If we can restrict eps to lie in the range  0 &lt; eps &lt; 1, then  <br>       N(eps) = 1.2*(1 + ln(1/eps)) / eps  <br>gives<br>       n^(1/n)  - 1]]></description>

        

            <jf:creationDate>Nov 26, 2012 5:04:23 PM</jf:creationDate>
            <jf:modificationDate>Nov 26, 2012 5:04:23 PM</jf:modificationDate>
            <jf:author>elgersma</jf:author>
            <jf:replyCount>0</jf:replyCount>
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        <item>
            <title>Find  N(eps) so that   n^(1/n)  - 1  &amp;lt; eps  for n &amp;gt; N(eps)</title>
        
            <link>http://mathforum.org/kb/thread.jspa?messageID=7923867&amp;tstart=0#7923867</link>

        

            <description><![CDATA[Find  N(eps) so that   <br><br>   n^(1/n)  - 1   &lt; eps    for n &gt; N(eps) for any eps &gt; 0<br><br>This is regarding   lim  n^(1/n)  =  1 (n]]></description>

        

            <jf:creationDate>Nov 15, 2012 8:04:54 PM</jf:creationDate>
            <jf:modificationDate>Nov 15, 2012 8:04:54 PM</jf:modificationDate>
            <jf:author>yulysh2000@yahoo.ca</jf:author>
            <jf:replyCount>1</jf:replyCount>
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