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Reason: Lim x app. inf. (2x+3)/(2x-1) is 1. Because if we carry out the division using polynomial division, we get]]> Dec 28, 2012 9:13:36 PM Dec 28, 2012 9:13:36 PM Peter Duveen 0 Re: L'Hospital's rule http://mathforum.org/kb/thread.jspa?messageID=7944181&tstart=0#7944181 ]]> Dec 27, 2012 8:10:07 AM Dec 27, 2012 8:10:07 AM GuyinMississippi 0 L'Hospital's rule http://mathforum.org/kb/thread.jspa?messageID=7943789&tstart=0#7943789 Can someone help me to solve this problem by L'Hospital's rule?

lim(x to infinity)((2x+3)/(2x-1))^((2x^2)/(x-1))

Thank U]]> Dec 26, 2012 10:32:33 AM Dec 26, 2012 10:32:33 AM ungeheuer 2