Math Forum http://mathforum.org/kb List of forum topics en Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8241084&tstart=0#8241084 Sum(n/n!, n=1 .. infinity) = Sum(1/k!,k = 0 .. infinity) = exp(1) <]]> Feb 2, 2013 5:14:18 PM Feb 2, 2013 5:14:18 PM &noreply@axelvogt.de 0 Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8240947&tstart=0#8240947 > On 02.02.2013 16:34, apovolot@gmail.com wrote:
 Feb 2, 2013 5:03:06 PM Feb 2, 2013 5:03:06 PM jacob@spamsink.net 1 Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8239245&tstart=0#8239245 > Hi,
>
> How close gets
>]]> Feb 2, 2013 2:56:39 PM Feb 2, 2013 2:56:39 PM &noreply@axelvogt.de 2 Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8237783&tstart=0#8237783 <apovolot@gmail.com> wrote:
>How]]> Feb 2, 2013 1:18:30 PM Feb 2, 2013 1:18:30 PM rouben@shady 0 Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8237782&tstart=0#8237782
I verified my result with maxima obtainibg some more digits

Here is the C version, then the]]> Feb 2, 2013 1:01:32 PM Feb 2, 2013 1:01:32 PM jacob@spamsink.net 0 Re: sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8236450&tstart=0#8236450 Hi

Here is a C program for you
----------------------------------------------------------cut here
/*Hi,

How close]]> Feb 2, 2013 11:33:28 AM Feb 2, 2013 11:33:28 AM jacob@spamsink.net 1 sum(eulerphi(n)/n!,n=1...infinity) = 5*sqrt(Pi)/3 -1 ???? http://mathforum.org/kb/thread.jspa?messageID=8235478&tstart=0#8235478
How close gets
sum(eulerphi(n)/n!,n=1...infinity)
to
5*sqrt(Pi)/3 -1
????

Regular (free that is) WolframAlpha gives]]> Feb 2, 2013 10:34:37 AM Feb 2, 2013 10:34:37 AM apovolot@gmail.com 6