http://mathforum.org/kb List of forum topics en http://mathforum.org/kb/thread.jspa?messageID=8359514&tstart=0#8359514 you are only going to get machine precision output. The way to get high]]> Feb 18, 2013 6:00:51 AM Feb 18, 2013 6:00:51 AM readhpr@gmail.com 0 http://mathforum.org/kb/thread.jspa?messageID=8359508&tstart=0#8359508
1. Use exact input:

In: N[(5/2)^125, 30]

Out:]]> Feb 18, 2013 6:00:18 AM Feb 18, 2013 6:00:18 AM svkeeley@aol.com 0 http://mathforum.org/kb/thread.jspa?messageID=8359505&tstart=0#8359505 Use N[(25/10)^125,30] to get the high-precision answer.

= 5.52714787526044456024726519219*10^49


The input has to be specified]]> Feb 18, 2013 6:00:03 AM Feb 18, 2013 6:00:03 AM tomdickens@att.net 0 http://mathforum.org/kb/thread.jspa?messageID=8359502&tstart=0#8359502 wrote:

>I am trying to evaluate 2.5^125 to high]]> Feb 18, 2013 5:59:47 AM Feb 18, 2013 5:59:47 AM readnews@sbcglobal.net 0 http://mathforum.org/kb/thread.jspa?messageID=8359501&tstart=0#8359501
> I am trying to evaluate 2.5^125 to high precision.
>
> R gives 5.527147875260445183346e+49 as the]]> Feb 18, 2013 5:59:42 AM Feb 18, 2013 5:59:42 AM awnl@gmx-topmail.de 0 http://mathforum.org/kb/thread.jspa?messageID=8351876&tstart=0#8351876
R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives]]> Feb 17, 2013 4:08:38 AM Feb 17, 2013 4:08:38 AM BlaiseFEgan 5