http://mathforum.org/kb List of forum topics en http://mathforum.org/kb/thread.jspa?messageID=1471713&tstart=0#1471713 Bravo!!

On Fri, 7 Apr 1995, Ted Alper wrote:

> Hey! I got it! Please bear with my ASCII diagrams.
>]]> Apr 8, 1995 3:01:56 PM Apr 8, 1995 3:01:56 PM tad@midget.towson.edu 0 http://mathforum.org/kb/thread.jspa?messageID=1471712&tstart=0#1471712
(for convenience, let's just worry about the CENTERS of the circles,
which lie in a 1 x]]> Apr 7, 1995 11:53:15 PM Apr 7, 1995 11:53:15 PM alper@Ockham.Stanford.EDU 1 http://mathforum.org/kb/thread.jspa?messageID=1471710&tstart=0#1471710 Alas, I cleverly deleted the problem. If I don't have it right, I]]> Apr 7, 1995 5:01:57 PM Apr 7, 1995 5:01:57 PM DENNIS@epub.ziff.com 0 http://mathforum.org/kb/thread.jspa?messageID=1471709&tstart=0#1471709 Jim:

Can you prove this?

The area of the rectangle is 2000 cm^2, and the circle is pi/4 cm^2. So,
if the coing was "soft", we]]> Apr 7, 1995 3:01:03 PM Apr 7, 1995 3:01:03 PM tad@midget.towson.edu 0 http://mathforum.org/kb/thread.jspa?messageID=1471708&tstart=0#1471708
>
> Does anyone have a proof to the following:
>
> Given]]> Apr 7, 1995 12:38:31 PM Apr 7, 1995 12:38:31 PM josborn@genesee.freenet.org 1 http://mathforum.org/kb/thread.jspa?messageID=1471707&tstart=0#1471707 Does anyone have a proof to the following:

Given a rectangular region of 2cm by 1000cm. You can fit 2011 (I think
it was 2011. It is]]> Apr 7, 1995 11:44:33 AM Apr 7, 1995 11:44:33 AM tad@midget.towson.edu 5