In article <lPqXh.firstname.lastname@example.org>, email@example.com writes: > In article <VE2FF$JAnAnfirstname.lastname@example.org>, email@example.com writes: >>Scalar product (multiplication of a scalar and a vector) gives rise >>to two division operations. Division of a vector by a scalar yielding >>a vector. Which is surely not controversial. And division of a >>vector by a vector yielding a scalar. Alas, this last operation is >>not very general since it requires that dividend and divisor be >>parallel. >> > No, it doesn't, it is just that it isn't unique. You can define a > multiplicative inverse (for dot product) of a vector v by the usual rule,
Note the parentheticals. I'm not talking about "scalar dot product". I'm talking about the product of a vector multiplied by a scalar.
If you invert aB = C for scalar a, vector B and vector C to derive "C divided by B is a" then B and C had better be parallel