On Tue, 7 Oct 2008 16:00:42 -0700 (PDT), the renowned email@example.com wrote:
>On Sep 30, 11:06 pm, Spehro Pefhany ><speffS...@interlogDOTyou.knowwhat> wrote: > >... > >> Maybe it would be easier if she filled three cups to the normal level, >> and then divided the total amount into four equal portions using a >> fourth empty cup, then discarded the left-over quarter and then >> combined the contents of the remaining three into one of the cups. ;-) > > >Speff, I don't quite understand what you mean by "the normal level".
Whatever level they normally fill them to-- what they consider a full serving.
>I typically fill my cups about 7/8 full. If that's a "normal level", >then 3 of those cups would be 7/8 + 7/8 + 7/8 = 21/8 cups.
>Dividing these into 4 cups of equal volume would give four cups each >containing 5.25/8 of a cup (neglecting the conic character of the >cups, of course).
Okay, so there's your 2/5 * 0.875 ("=full") - 5.25/8 in each of four cups.
>Discarding one of these cups, and adding the 3 x (5.25/8) cup gives >1.97 cups. So now I'm absolutely baffled how that could ever equal >0.750 cup.
Indeed. The final emptying would just make an ungodly mess, so just give you one and discard the rest.
>> In practice I'd just ask her to fill it and dump out the excess >> myself-- it would be the fastest way. > > ><big cheesy grin> > > >> Best regards, >> Spehro Pefhany >> -- >> "it's the network..." "The Journey is the reward" >> sp...@interlog.com Info for manufacturers:http://www.trexon.com >> Embedded software/hardware/analog Info for designers: http://www.speff.com > > >Michael
Best regards, Spehro Pefhany -- "it's the network..." "The Journey is the reward" firstname.lastname@example.org Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com