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Topic: Re: Trisecting an arbitrary angle
Replies: 62   Last Post: Oct 2, 2017 1:58 AM

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 bassam king karzeddin Posts: 2,085 Registered: 8/22/16
Re: Trisecting an arbitrary angle
Posted: Oct 1, 2017 4:42 AM

On Sunday, October 1, 2017 at 11:28:53 AM UTC+3, Zelos Malum wrote:
> Den onsdag 3 maj 2017 kl. 19:50:05 UTC+2 skrev bassam king karzeddin:
> > >
> > >
> > >
> > > Le 19/07/05 12:37, dans
> > > 4dd7d\$42dcd769\$d52f93dc\$25956@news.chello.at,
> > > « Jutta Gut » <gut.jutta.gerhard@chello.at> a écrit :
> > >

> > > >
> > > > "bassam king karzeddin" <bassam@ahu.edu.jo> schrieb

> > > im Newsbeitrag
> > > >
> > > news:29354512.1121766911405.JavaMail.jakarta@nitrogen.
> > > mathforum.org...

> > > >> That is grate,
> > > >>
> > > >> This,might open doors to constructible polygons
> > > >>
> > > >> In fact,I have deduced & proved the same thing,I

> > > have mentioned that here:
> > > >>
> > > >>

> > > http://mathforum.org/kb/message.jspa?messageID=3802920
> > > &tstart=0

> > > >>
> > > >> I will provide examples soon.

> > > >
> > > > If I understand correctly, you have shown that in

> > > an triangle with
> > > > the sides a^3 , a*(b^2-a^2) , b*(b^2-2*a^2) one
> > > angle is three times
> > > > another one.
> > > >
> > > > The more interesting question would be: given an

> > > angle, how to
> > > > construct a triangle with the sides a^3 ,
> > > a*(b^2-a^2) , b*(b^2-2*a^2)
> > > > and the given angle?
> > >
> > > It tried for some simple angles: pi/8, pi/6, pi/5,
> > > sides can be computed
> > > with square roots. For pi/9, you have the 3rd degree
> > > equation x^3=3*x+1.
> > > Not surprising, since pi/9 is not constructible. But
> > > it's still interesting
> > > to know which triangles have two angles A,B such that
> > > A=3*B.
> > >

> >
> > That is because there is not any EXACT real root for the polynomial (x^3 - 3x -1 = 0), for sure, but nearly an approximated root, and that is why your in mind angle (Pi/9) is never an exact existing angle
> >
> > So, understanding that fiction unreal and nonexistent number as 2^{1/3} would immediately remove the complete puzzle about trisecting of the arbitrary angle
> >
> > And let us see what works that had been added by secretive researchers or Wikipedia writers? after that old date reference and what are the rules of this science forum or the rules of professional mathematicians to promote that old interesting issue raised by a mature only to the science community
> >
> > Regards
> > Bassam King Karzeddin
> > 3ed, May 2017

>
> We can find the result for that easily, the issue is more you do not understand the rules of the game.

Yes, and true, they made mathematics as a game, but they must confess it clearly as a game and not bothering the whole population about its UNLOGICAL rules for sure

BKK

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