Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
NCTM or The Math Forum.


Math Forum
»
Discussions
»
sci.math.*
»
sci.stat.math
Notice: We are no longer accepting new posts, but the forums will continue to be readable.
Topic:
covariance matrix, correlation matrix, decomposition
Replies:
4
Last Post:
Nov 24, 1999 5:37 AM




Re: covariance matrix, correlation matrix, decomposition
Posted:
Nov 24, 1999 5:11 AM


Michael Pronath <mcp@eda.ei.tum.de> writes:
> It is often necessary to decompose a given covariance matrix C > (resp. correlation matrix R) as C=G*G'. Cholesky decomposition is > commonly used here. > But there are some others possible. Starting from the eigenvalue > decomposition C=Q*L*Q', there is > > G1 = Q*sqrt(L), as G1*G1' = Q*sqrt(L)*sqrt(L)*Q'=Q*L*Q' = C > > or > > G2 = Q*sqrt(L)*Q', as G2*G2' = Q*sqrt(L)* Q'*Q *sqrt(L)*Q' = > = Q*sqrt(L)* 1 *sqrt(L)*Q' = C > > ... > > I'd like to know if anybody has made some more profound analysis about > this, and the pro's and con's of the various methods.
Sargis Dallakyan <sargis@cerfacs.fr> writes:
> IMO if you have a covariance matrix and want to decompose it then sure > enough Cholesky is the best. But if you want to generate a random > vectors with a desired confidence ellipsoid then 2) and 3) gives you a > direct way to do that.
Why do you think that Cholesky is the best? It is commonly used for that task, and I wanted to know the reason.
Helmut Jarausch <jarausch@igpm.rwthaachen.de> writes:
> What about an SVD of G (not C !) Just computing C (not even > decomposing) makes the condition number worse. Say, you have the > SVD of G : G = U S V' where U and V are orthogonal matrices and S > has nontrivial elements only on its diagonal. Then G*G' = U S S' U' > where SS' has the diagonal (s_{ii}^2) and zeros elsewhere. You can > extract all information about C from U and S and it should be much > more.
Indeed, if T is the diagonal matrix of the standard deviations, and R is the correlation matrix, then C=T*R*T'. Then, the decomposition G*G'=C=T*R*T' and so inverse(T)*G*G'*inverse(T') = R = H*H', with H=inverse(T)*G. So, it is probably better to decompose R=H*H' (and then calculate G=T*H if necessary).
Nevertheless, for the decomposition R=H*H', the same options remain: Cholesky or Eigenvalue I or II? Which is when the best and why?
At a first glance, I like Eigenvalue I best, because it generates orthogonal grids. As C and R are symmetric, and the number of statistical parameters is commonly < 100, the eigenvalue decomp. should be fast and stable. Plus, the parameter ordering does not influence the decomposition, as it does in Cholesky.
As the decomposition R=G*G' is frequently used when generating random numbers, grids in statistical parameter spaces, etc., I assume that somebody has already performed an analysis of this, but where?
Michael Pronath




