
RE: Probability of a Triangle
Posted:
Sep 19, 2004 9:07 AM


On Wed, 15 Sep 2004 16:29:58 +0100, Ballew, Pat wrote: > >I think I want to try the most direct, what if >the probability of selecting either >stick was in the ratio of their length to the whole, >so if part a was 1/4 " >and part B was 3/4 " then the prob of picking A is >1/4 and the prob of >picking B is 3/4... A nice >extension to the problem.... Any quick solutions? >
This is pretty simple. For a given h the probability was found to be h/(1h). Assuming h < 1/2, this event will occur with probability (1h), such that we'll have to integrate [h/(1h)](1h) from 0 to 1/2, with the subsequent multiplication by 1/2. The result is 1/4.
Alexander Bogomolny http://www.cuttheknot.org
P.S. I found additional sources for the problem and relevant questions and am going to expand the article at my site.

