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Topic: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Replies: 9   Last Post: Oct 12, 2012 4:51 PM

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Posts: 67
Registered: 3/17/12
Re: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted: Apr 11, 2012 2:53 PM
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The ratio between the Rydberg mass, 1.7951598x10^8, and the proton mass is 1.073260262x10^35. Divide this by the Rydberg multiplier, 2.956762509x10^32, and you find 3.62984932x10^2. This comprises the quantum adjustor, 3.62994678x2 divided by Gc. The quantum adjustor formula is 4/{4h(c/2)^4}^0.3333rec. If we break up the Rydberg multiplier into component parts we see 2(c^2)x(Rydberg- frequency)x(3.62994678)/Gc=M/m.
Interestingly, this comprises one whole G yet the Rydberg mass answers to the Planck mass which comprises a component of only G^0.5. How can this be?
There are a few more symmetries to M/m. Twice the Rydberg frequency multiplied by the Planck mass equals the Rydberg mass because Rydberg mass/Planck mass = twice frequency. So, (c^2)(Rydberg mass/Planck mass)/Gc is also equal to Rydberg Mass/proton mass. There are more symmetries. (c/G)(Rydberg mass/Planck mass)(3.62994678) equals 1.073260262x10^35.
Here is another. Remember 29.6906035 is the Gm product whose Schwarzschild diameter is equal to the proton wavelength, 1.32141x10^-15m.
And, (29.6906036xRydberg massx4)/(ch) is also equal to Rydberg mass/proton mass.
(hc/4) is equivalent to Gm^2 where m is the Planck mass. The reciprocal is 2.013645x10^25. Multiply this by 64 and find the cube root and you have 1.08823066x10^9 which plays a number of roles in this branch of physics.
(1.0882366x10^11)x(Rydberg mass/Planck mass)/G=1.073260262x10^35.

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