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Topic: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Replies: 9   Last Post: Oct 12, 2012 4:51 PM

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Posts: 67
Registered: 3/17/12
Re: SONNTAG! Symmetries of Nature 'n' Truth about Gravity(& Planck Units).
Posted: May 30, 2012 3:34 PM
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Another way of looking at the Hydrogen atom, other than the Rydberg
Multiplier method, is as follows: Because the proton is that much
smaller than the Planck mass the theoretical surface g is likely to be
higher than c(equivalence) necessitating a rise in the event horizon
bringing its diameter nearer to the size of its Compton wavelength.
This results in a Lorentz transformation of the proton's Gm product to
29.6906036. This multiplied by the proton mass, 1.672623x10^-27kg, is
4.966118653x10^-26, which is equal to hc/4 and also equal to the Gm^2
product of G times the Planck mass squared. The electron speed is
2.187691412x10^6 ms so the electron Compton wavelength will be
3.324918617x10^-10m; divide this into hc/4 and you get
1.49360607x10^-16. Divide this by the Rydberg energy and you get
137.035989/2, the reciprocal of the fine structure constant/2. We can
bypass this with hv, using the electron speed, above, we get


We can apply the same reasoning to the deuterium atom as follows:
One nucleon is ascribed an energy of 1.78204x10-13 J, a speed
equivalent to 1.03219017x10^7ms and a wavelength of
1.91896991x10^-14m. (hc/4)/1.91896991x10^-14m equals
2.587908558x10^-12. Divide this by the Deuterium nucleon energy of
1.78204x10^-13 J and you get 14.52216869.
Using the hv principle above, hx1.03219017x10^7ms=6.839369997x10-27.
Divide this by 1.44958084x10^-27, above, and you get 4.718170781.
Multiply this by 14.52216869, above, and you get 137.035989. This is
because c/v=29.04427537 and 29.6906036 divided by
29.04427537=1.022253206. Multiply this by two and you get 2.044506412;
multiply by the proton mass and divide by the wavelength
1.9189699x10-14m and you get 1.7820438x10^-13 J, the nucleon energy.

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