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Topic: plot of function of two variables
Replies: 4   Last Post: Oct 14, 2012 12:23 AM

 Messages: [ Previous | Next ]
 Bob Hanlon Posts: 906 Registered: 10/29/11
Re: plot of function of two variables
Posted: Oct 14, 2012 12:18 AM

\$Version

"7.0 for Mac OS X x86 (64-bit) (November 11, 2008)"

Manipulate[
ContourPlot[(x - a)^2 + (y - b)^2 == r^2,
{x, a - r, a + r},
{y, b - r, b + r},
Frame -> False,
Axes -> True,
AxesLabel -> {"x", "y"},
PlotRange ->
{{-15.5, 15.5}, {-15.5, 15.5}}],
{{a, 0}, -5, 5, 1, Appearance -> "Labeled"},
{{b, 0}, -5, 5, 1, Appearance -> "Labeled"},
{{r, 5, "|r|"}, 1, 10, 1,
Appearance -> "Labeled"}]

Manipulate[
Plot[Evaluate[y /.
Solve[(x - a)^2 + (y - b)^2 == r^2, y]],
{x, a - r, a + r},
AspectRatio -> 1,
FrameLabel -> {"x", "y"},
PlotRange ->
{{-15.5, 15.5}, {-15.5, 15.5}}],
{{a, 0}, -5, 5, 1, Appearance -> "Labeled"},
{{b, 0}, -5, 5, 1, Appearance -> "Labeled"},
{{r, 5, "|r|"}, 1, 10, 1,
Appearance -> "Labeled"}]

Bob Hanlon

On Sat, Oct 13, 2012 at 1:03 AM, Miguel Aragon <aragon.miguel@gmail.com> wrote:
>
> I have a question about how to plot a function of two variable of the form
> (x-a)^2 + (y-b)^2 = r^2 with Mathematica v 7.0? Is it possible?
>
> Thank you,
>
> --
> Miguel Aragon
> aragon.miguel@gmail.com
>
>

Date Subject Author
10/14/12 Bob Hanlon
10/14/12 Rodrigo AP
10/14/12 Murray Eisenberg
10/14/12 Chris Arthur