Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Topic: Dimension of the space of real sequences
Replies: 21   Last Post: Nov 19, 2012 10:22 AM

 Messages: [ Previous | Next ]
 Jose Carlos Santos Posts: 4,896 Registered: 12/4/04
Re: Dimension of the space of real sequences
Posted: Nov 14, 2012 8:57 AM

On 14-11-2012 10:19, quasi wrote:

>> Can someone please tell me how to prove that the real vector
>> space of all sequences of real numbers has uncountable
>> dimension?

>
> Let V be the set of infinite sequences of real numbers, regarded
> as a vector space over R.
>
> For each a in R, let v_a = (e^a,e^(2a),e^(3a),...).
>
> Let S = {v_a | a in R}.
>
> S has the same cardinality as R, hence S is uncountable.
>
> Claim the elements of S are linearly independent over R.
>
> Suppose otherwise.
>
> Let n be the least positive integer such that there exist
> n distinct real numbers a_1, ..., a_n such that
>
> v_(a_1), ..., v_(a_n)
>
> are linearly dependent over R.
>
> Without loss of generality assume a_1 < ... < a_n.
>
> Then
>
> (c_1)*(v_(a_1)) + ... + (c_n)*(v_(a_n)) = 0
>
> for some real numbers c_1, ..., c_n.
>
> By minimality of n, it follows that c_1, ..., c_n are
> all nonzero.
>
> Then
>
> (c_1)*(v_(a_1)) + ... + (c_n)*(v_(a_n)) = 0
>
> implies
>
> (c_1)*(e^(k*(a_1))) + ... + (c_n)*(e^(k*(a_n))) = 0
>
> for all k in N.
>
> Dividing both sides by e^(k*(a_n)), we get
>
> (c_1)*(e^(k*(a_1 - a_n))) + ... + c_n = 0
>
> for all k in N.
>
> Taking the limit of both sides as k -> oo yields c_n = 0,
>
> Hence the elements of S are linearly independent over R, as
> claimed.
>
> It follows that the dimension of V over R is uncountable.

Thanks for the proof.

Best regards,

Jose Carlos Santos

Date Subject Author
11/13/12 Jose Carlos Santos
11/13/12 Mike Terry
11/14/12 Jose Carlos Santos
11/14/12 Mike Terry
11/13/12 Ken.Pledger@vuw.ac.nz
11/13/12 Virgil
11/14/12 Jose Carlos Santos
11/14/12 Shmuel (Seymour J.) Metz
11/13/12 archimede plutanium
11/14/12 Robin Chapman
11/14/12 David Bernier
11/14/12 Jose Carlos Santos
11/14/12 Robin Chapman
11/14/12 Jose Carlos Santos
11/14/12 quasi
11/14/12 Jose Carlos Santos
11/14/12 W^3
11/15/12 David C. Ullrich
11/15/12 Butch Malahide
11/15/12 W^3
11/18/12 David Bernier
11/19/12 David C. Ullrich