
Re: Curvature in Cartesian Plane
Posted:
Nov 15, 2012 5:28 AM


On Thu, 15 Nov 2012, Brad Cooper wrote: > "Mike Terry" <news.dead.person.stones@darjeeling.plus.com> wrote in message > While investigating this I came across this in Spiegel's Vector Analysis: > > The radius of curvature rho of a plane curve with equation y = f(x), > i.e. a curve in the xy plane is given by > > rho = sqrt(1+(y')^2) / y'' > No, rho = (1 + y'^2)^(3/2) / y"
> I tested this with the simple hemisphere y = sqrt(1x^2).
That's a semicircle.

