
Re: definition of closure in topological space question
Posted:
Nov 18, 2012 2:44 AM


On Sun, 18 Nov 2012, David Hartley wrote: > Elliot <marsh@panix.com> writes
> > > > > 2. cl(A) is the intersection of all neighborhoods containing > > > > > A, where a neighborhood is any set containing an open set (an > > > > > element of the topology). > ... > > OP is neither confused nor incorrect about 2. As he indicated, it's a metric > > space definition and in fact, in any metric space, 1 and 2 are equivalent. > > If A is open then it is a neighbourhood containing A, and so under 2, > cl(A) = A. How simple and direct.
> That is not equivalent to the usual definition in any space which has an > open set which is not closed. In particular, it is only equivalent in a > T1 space if it is discrete. > > Make it *closed* neighbourhoods of A in 2 and then it's equivalent to > usual closure in T1 normal spaces, even regular spaces. (Probably it's > equivalent if and only if the space is regular.)
More than T1 is needed for by 2, within the cofinite reals, cl {0} = R.
Can you show the equivalence for normal T1 spaces?

