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Re: simplifying rational expressions
Posted:
Jan 16, 2013 7:18 AM
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"stony" <x@x.com> escreveu na mensagem
news:uqfcf8dvhsqr7qjsdi09b8agcahbsr98ah@4ax.com...
> Hi,
> Need a little help with this. We are simplifying the following, but
> the solution is pretty lengthy and messy because of the enormous
> number of factors. I was thinking that may be I am missing seeing a
> pattern (some series or something). Is grunt work the only way to
> solve this or is there a pattern that can simplify the whole process?
> My daughter was trying to solve this, but ended up with the mess and
> then I got the same mess, but I thought there may be an easy way to
> simplify this that I may be missing.
> ((b-c)/((a-b)(a-c))) + ((c-a)/((b-c)(b-a))) + ((a-b)/((c-a)(c-b))) +
> (2/(b-a)) - (2/(c-a))
> of course, I took all the factors in the denominator and then started
> multiplying the numerator with the remaining factors to end up with a
> mess.
> Your help is appreciated.
> s
Hi Stony.
With the help of Google I've found this site:
http://www.quickmath.com/webMathematica3/quickmath/algebra/factor/basic.jsp
As I've seen, it works OnLine, so you'll get a solution immediately.
I hope this will help you.
Bye,
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