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Topic: Low precision exponentiation
Replies: 5   Last Post: Feb 18, 2013 6:00 AM

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Tom D

Posts: 7
Registered: 8/4/10
Re: Low precision exponentiation
Posted: Feb 18, 2013 6:00 AM
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Use N[(25/10)^125,30] to get the high-precision answer.

= 5.52714787526044456024726519219*10^49

The input has to be specified to at least the desired precision.
Mathematica treats 2.5 as a machine-precision number.

Hope that helps,

On Sun, 17 Feb 2013 09:08:38 +0000 (UTC), Blaise F Egan
<> wrote:

>I am trying to evaluate 2.5^125 to high precision.
>R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision.
>I am inexperienced at Mathematica. Am I doing something silly?

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