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Topic: Low precision exponentiation
Replies: 5   Last Post: Feb 18, 2013 6:00 AM

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 Tom D Posts: 7 Registered: 8/4/10
Re: Low precision exponentiation
Posted: Feb 18, 2013 6:00 AM

Use N[(25/10)^125,30] to get the high-precision answer.

= 5.52714787526044456024726519219*10^49

The input has to be specified to at least the desired precision.
Mathematica treats 2.5 as a machine-precision number.

Hope that helps,
Tom

On Sun, 17 Feb 2013 09:08:38 +0000 (UTC), Blaise F Egan
<blaise@blaisefegan.me.uk> wrote:

>I am trying to evaluate 2.5^125 to high precision.
>
>R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision.
>
>I am inexperienced at Mathematica. Am I doing something silly?
>
>Blaise

Date Subject Author
2/17/13 Blaise F Egan
2/18/13 Albert Retey
2/18/13 Bill Rowe
2/18/13 Tom D
2/18/13 svkeeley@aol.com