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Topic: Computationally efficient method of assessing one measure of
variation of a function

Replies: 2   Last Post: Feb 24, 2013 9:41 PM

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 William Elliot Posts: 2,634 Registered: 1/8/12
Re: Computationally efficient method of assessing one measure of
variation of a function

Posted: Feb 23, 2013 10:37 PM

On Fri, 22 Feb 2013, pepstein5@gmail.com wrote:

> Let N be a positive integer. Let f be a function from the nonnegative
> integers <= N to the reals. Let d > 0. What is a computationally
> efficient way of finding the largest possible k such that there exists M

> >=0, M + k <=N such that abs(f(x) - f(y)) <= d for all x, y such that x
> and y are both >= M and <= M + k?

What's the ranges of the variables? Reals, integers, positive integers?

> I'm also interested in continuous analogies. For example, suppose f is
> a continuous function defined on a closed interval. How do we find the
> length of the longest interval I in the domain of f such that abs(f(x) -
> f(y)) <= d whenever x and y both lie in I.

For continuous f:[a,b] -> R and d > 0, you want to find the largest
interval I subset [a,b] with the lenght of the interval f(I) <= d?

That is highly dependent upon how f varies.
If f is constant, then I = [a,b].

If f(x) = x, then I = [a, a+d] if a+d <= b
is one maximal interval among possibly uncountable many.
If b < a + d, then I = [a,b].

If f(x) = rx, r > 0, then I = [a, a+d/r] if a+d/r <= b
is one maximal interval among possibly uncountable many.
If b < a + d/r, then I = [a,b].

In general, if len f([a,b]) <= d, [a,b] is the maximum interval.
It seems to me that the maximal intervals would be associated
where |f"| is the smallest.

Date Subject Author
2/22/13 Paul
2/23/13 William Elliot
2/24/13 James Waldby