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Topic: Parallelogram Orthocenters
Replies: 7   Last Post: Oct 22, 2013 7:28 AM

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Registered: 9/16/06
Re: Parallelogram Orthocenters
Posted: Oct 16, 2013 6:57 AM
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Hi Avni,

I suppose locating orthocenter by finding altitudes ( = 2 Area of triangles / base ) etc. can be done.

By geometric construction H1H2 ~ 7.57188, its component parallel to AB is 7. It can be noted that O, midpoint of DB or H1H2 is the anti-symmetric centre of opposite vertices of parallelogram ABCD.


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