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Re: Parallelogram Orthocenters
Posted:
Oct 16, 2013 6:57 AM


Hi Avni,
I suppose locating orthocenter by finding altitudes ( = 2 Area of triangles / base ) etc. can be done.
By geometric construction H1H2 ~ 7.57188, its component parallel to AB is 7. It can be noted that O, midpoint of DB or H1H2 is the antisymmetric centre of opposite vertices of parallelogram ABCD.
Regards Narasimham



