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Topic: Altitude ratios of two tetrahedra
Replies: 2   Last Post: Dec 15, 2013 11:53 AM

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 Peter Scales Posts: 192 From: Australia Registered: 4/3/05
Re: Altitude ratios of two tetrahedra
Posted: Dec 15, 2013 11:53 AM

> Let's say that you have two tetrahedra, call them A
> and
> B.
>
> Tetrahedron A has an altitude of 1H. You insert
> tetrahedron B into A an rotate it so that all of its
> Vertices are pointing in the opposite director of the
> vertices of A, and all of its faces are parallel to
> the vertices of A. You find that the distance
> between one face of A is 4.6 H away from the parallel
> face of B.
>
> What is the altitude of B? Thanks in advance.

Patrick,
Let altitude of B be x
Centroid is 1/4 of height from base
So 1.H/4+x/4 = 4.6H
x=17.4H
Regards, Peter Scales.

Date Subject Author
12/14/13 Patrick D. Rockwell
12/15/13 Narasimham
12/15/13 Peter Scales