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Topic: Matrix dimensions must agree.
Replies: 13   Last Post: Mar 24, 2014 5:34 PM

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Steven Lord

Posts: 2,237
Registered: 9/26/13
Re: Matrix dimensions must agree.
Posted: Mar 21, 2014 9:46 AM
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"Vitor Andrade" <> wrote in message
> "Vitor Andrade" wrote in message
> <lgfgag$34p$>...

>> dpb <> wrote in message <lgfaqk$820$>...
>> > On 3/20/2014 12:57 PM, Vitor Andrade wrote:


> Sr. When I was analyse other data, now, I have a new problem, the matrices
> with different sizes;
> a =
> [0.400000000000000,35139.0781250000;0.933333333333333,32986.5703130000;1.50000000000000,30094.9824220000;2.26905,25000.00000;2.50000000000000,23203.3417970000;3.0666666666666,19190.0585940000;3.60000000000000,
> 5137.0966800000;4.16666666666667,10913.9882810000;4.80000000000000,6466.71191400000;5.36666666666667,2564.06420900000;5.86666666666667,377.535583000000]
> size(a)
> 11x2
> b =
> [0.633333333333333,34091.8632810000;1.23333333333333,31666.7167970000;1.73333333333333,28622.0957030000;2.23333333333333,25087.7421880000;2.76666666666667,21232.4296880000;3.33333333333333,17193.9140625000;3.86666666666667,13042.4101560000;4.46666666666667,8754.32812500000;5.10000000000000,4451.73877000000;5.66666666666667,1339.44116200000]
> size(b)
> 10x2

>>>x = length(a);
>>>y = length(b);

You shouldn't really use LENGTH on matrices, because you can't be certain
that it's telling you what you want to know. [Both a and a' have the same
LENGTH, for example, but very different numbers of rows.] But you're
interested in the number of rows each of a and b have. Instead, use SIZE to
get the size of the matrix _in a specific dimension._

x = size(a, 1); % number of rows in a
y = size(b, 1); % number of rows in b

>>> if x > y

> a(y+1:end)=[];

This is an indexing technique known as linear indexing as described in the
section with that name on this page:

Instead you want to use subscripted indexing, as described in the "Accessing
Multiple Elements" section on that same page.

> else
> if y > x
> b(x+1:end)=[];
> end
> end

I wouldn't use this approach; I'd instead select the elements to keep. It
avoids the IF and ELSEIF statements at the expense of a call to MIN:

minRows = min(x, y);
a = a(1:minRows, :);
b = b(1:minRows, :);

> However, I expected to find:
> a =
> [0.400000000000000,35139.0781250000;0.933333333333333,32986.5703130000;1.50000000000000,30094.9824220000;2.26905,25000.00000;2.50000000000000,23203.3417970000;3.0666666666666,19190.0585940000;3.60000000000000,
> 5137.0966800000;4.16666666666667,10913.9882810000;4.80000000000000,6466.71191400000;5.36666666666667,2564.06420900000];
> And 'b' were equal.
> But my result was:
> a =
> [0.4000,0.9333,1.5000,2.0000,2.5000,3.0667,3.6000,4.1667,4.8000,5.3667];

Yes, because you treated a as though it were a vector.

> You can help me? Please?
> I hope your answer. Thanks so much!

Based on the questions you've been asking, I'm guessing you're fairly new to
MATLAB or that it's been a while since you last used it. Is that the case?
If so, I recommend you go through the Getting Started documentation. In my
opinion it provides a good introduction or refresher on the basics of
working with MATLAB, including indexing into arrays. If you open the
documentation using the DOC function:


and select MATLAB, you should see something that looks like this page in the
documentation browser:

"Getting Started" is right above the Language Fundamentals section.

Steve Lord
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