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Re: Three points on incircle
Posted:
Apr 28, 2014 4:44 PM
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Hi Peter,
thanks for the contribution. The structure has an interesting property. Let BE = x, then the power of B with respect to the incircle is x*(1+x)= 1, or x = (sqrt(5)-1)/2, so we have the golden ratio.
The next problem is as follows:
Let A=[-1,-1], B=[1,-1]. Construct points D, E, F on the unit circle, such that line DE is parallel to the y-axis, and triples {B,E,F], {A,F,D} are collinear respectively.
Best regards,
Avni
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