Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
NCTM or The Math Forum.


Math Forum
»
Discussions
»
sci.math.*
»
sci.math
Notice: We are no longer accepting new posts, but the forums will continue to be readable.
Topic:
A very hard equation
Replies:
9
Last Post:
Oct 29, 2004 10:38 AM



wes
Posts:
24
Registered:
12/13/04


Re: A very hard equation
Posted:
Oct 26, 2004 7:40 PM


In article <261020041356130641%anniel@nym.alias.net.invalid>, anniel@nym.alias.net.invalid says... > In article <MPG.1be839c888c1561e989691@news.west.earthlink.net>, wes > <wesh@acm.org> wrote: > > > In article <c0e2bfb2.0410260454.370292a9@posting.google.com>, > > ramtin13682002@yahoo.com says... > > > (x+1)^1/3+4(1x)^1/3=41x^2 > > > > > > > > > > Mathematica gets > > > > x = (1/6)*(3  5*Sqrt[57]), (1/6)*(3 + 5*Sqrt[57]) > > > > wesh > > Mathematica assumes (x+1)^1/3 means ((x+1)^1)/3, and then > this is the solution. But humans assume (x+1)^1/3 means (x+1)^(1/3), > and then this is not the solution. > Mea culpa!



