
Re: Solving inequalities that involve abs value functions
Posted:
Jan 5, 2005 1:52 AM


ivan999@remove34this.iprimus.com.au wants algebra help: > >I'm trying to solve 2x+3 <= 3x+7 > >(1) >2x+3 <= 3x+7 >2x <= 3x+4 >x <= 4 >x >= 4 > >(2) >2x3 <= 3x+7 >2x <=3x+10 >5x <= 10 >x <= 2 > >WRONG! The correct solutions are x<= 4 and x>= 2 but I don't understand >how to get these solutions algebraically. > >TIA >Ivan.
Without checking reference to a good algebra textbook, it seems you may have left out two more possibilities; but in any case, in your condition #2, you forgot to switch the direction of the order relation symbol when you divided by negative 5. You should obtain x >= 2;
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