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Re: Modern censorship
Posted:
Nov 20, 2004 2:59 PM
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jstevh@msn.com (James Harris) wrote in message news:<3c65f87.0411171706.3f79aba8@posting.google.com>...
> You read in history books about individuals harried by mobs,
>
[snip lengthy diatribe]
>
> You people cheat.
>
[snip whining about cheats]
>
>
> They are cows, and cowards.
[snip whining about cows and cowards]
>
> And I will win. I have a paper at a major math journal. If they try
> to slide out of publication like others before them, it will go to
> another, and another, and another, as I adjust, shift the wording,
> learn the game, play the politics necessary to get published.
>
Just curious: the most recent version of your paper on polynomial
factorization, co-authored by you and A. Beckwith, at:
<a href="http://www.ne-plus-ultra.net/index.php?option=content&task=view&id=46&Itemid=26">http://www.ne-plus-ultra.net/index.php?option=content&task=view&id=46&Itemid=26</a>
includes the following material toward the end:
"Now letting m = 1, f = sqrt(5), where I can let u = 1 as its
value doesn't change the a's, I have
(m^3 f^6 - 3 m^2 f^4 + 3 m) x^3 - 3 (-1 + m f^2) x u^2 + u^3
= 65 x^3 - 12 x + 1 ..."
But clearly, if you substitute m = 1, f = sqrt(5), and u = 1
into the expresson on the left side, you get:
53 x^3 - 12 x + 1.
So that's obviously wrong.
Not only that, but your original polynomial in that paper is
written as
P(m) = f^2 ((m^3 f^4 - 3 m^2 f^2 + 3 m) x^3 - 3(-1 + m f^2)x u^2 + u^3 f).
Now, if I substitute m = 1, f = sqrt(5), u = 1 into THIS
expression, I get:
P(m) = 65 x^3 - 60 x + 15 sqrt(5)
which of course ALSO does not equal
65 x^3 - 12 x + 1.
So what I am curious about is: is this the version you have
submitted to a journal?
Andrzej
[snip still more whining]
>
> And humanity is so much the worse for all of the stink of it.
>
>
> James Harris
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