Bob
Posts:
27
Registered:
1/29/05


Re: Rectangle with maximum area
Posted:
Feb 27, 2005 8:17 PM


On Mon, 28 Feb 2005 00:47:36 +0000 (UTC), rasputin16002002@yahoo.co.uk (newatthis) wrote:
>hello >Rectangle has a perimeter of 68.Find the lengths of those sides that >give you maximum area for that rectangle > >2a+2b=68 > >a*b=A >
Substitute first eqn in the second, so you have A as a function of one variable. Differentiate...
bob

