I pondered: >> While we're at it, I've often wondered how much a head weighs. How can I >> weigh my own head? Seriously.
and Carl G replied: > The standard method is based on the fact that the density of a head is > approximately the same as the density of water. ...
I had considered the Archimedean method but didn't know that heads are as dense as water. If I didn't have density information, how might I do it?
For example, suppose my doctor tells me I need to lose 50 pounds, and I'm trying to decide whether to do it by diet and exercise, or just take the easy weigh out and have a leg amputated. Since my leg might not weigh 50 pounds, I'll have to lose some weight by exercise before the amputation. How will I know how much to do?