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Posted:
Nov 18, 2005 3:24 PM
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Date: Thu, 17 Nov 2005 20:36:19 -0500
To: numeracy@europe.std.com
From: Ed Wall <ewall@umich.edu>
Subject: Re:
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Actually I tried the 'dozen' approach first, but
while this would make a sort of sense then the
price for three less does not (i.e. 3 less from a
dozen is not a dozen) as you still seem to be
figuring the price per egg. So I would argue that
appealing to common sense fails (smile). Also, so
as to make things more interesting, I note that
there are (or used to be as I haven't done this
in awhile) places where you could commonly buy
half cartons of eggs.
So let me pose a different problem. How many of
the answers admit a more or less plausible (or
moderately implausible) interpretation?
Ed Wall
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>Subject: RE:
>Date: Tue, 15 Nov 2005 16:28:58 -0700
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>From: "Lauser, Don" <dlauser@tvi.edu>
>To: <numeracy@europe.std.com>
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>The egg problem:
>Due to a 30% increase in the price of eggs, 3
>less eggs are available for £7.80. Is the
>present rate of eggs per dozen:
>a) £8.64
>b) £9.36
>c) £8.88 or
>d) £10.40? and how did you get that?
>
>It really depends on how you read the problem
>and the assumptions you make. If you assume
>that the 7.80 is both the price of eggs previous
>to the increase and also of the eggs minus 3
>after the increase, then Ed Wall's solution
>makes sense. --B. 9.36
>This is a reasonable reading of the problem but
>not the only way to look at it. It also
>contradicts the common sense notion that eggs
>are sold by the dozen, but it is more
>mathematically pure because one shouldn't assume
>anything not specifically written in the
>problem, (although it does assume the same price
>of 7.80 which I do not think is evident in the
>writing of the problem.)
>
>But if you read it as I did, making the
>assumption that the eggs both previously and
>currently were sold by the dozen (since the
>question asks about price per dozen) and that
>the 7.80 is the new price of a dozen eggs less
>3, (and the old price is an unknown,) you then
>can figure the new price per egg as 7.80/9 and
>multiply the result by 12 to get the new price
>per dozen: D. 10.40 in which the 30% increase
>is unnecessary information.
>
>However if you truly leave out both assumptions,
>your new price per egg times the new number of
>eggs would equal 7.80, looking like this in
>equation form:
>
>[(1.3)P/E][E-3]=7.80
>
>where P= old price of the eggs and E = the
>original number of eggs at the old price.
>
>But I think this leaves the problem insoluble as
>there is not enough information given, unless
>you return to assuming either A. Eggs are only
>sold by the dozen--both previous to and after
>the increase in price, or B. 7.80 is both the
>price of eggs previous to the increase and also
>of the eggs minus 3 after the increase.
>
> Are there any holes in my reasoning?
>
>Don Lauser
>
>
>
>-----Original Message-----
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>Behalf Of Esther D Leonelli
>Sent: Sunday, November 13, 2005 10:23 AM
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>From: becci <discussions@mathforum.org>
>To: numeracy@world.std.com
>Subject: eggs situation need help!!
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>due to a 30% increase in the price of eggs, 3
>less eggs are available for £7.80.is the
>present rate of eggs per dozen is:
>a) £8.64
>b) £9.36
>c) £8.88 or
>d) £10.40? and how did you get that?
>
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