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Topic: binomials fractions
Replies: 1   Last Post: Jan 18, 2006 3:34 AM

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ticbol

Posts: 116
Registered: 1/25/05
Re: binomials fractions
Posted: Jan 18, 2006 3:34 AM
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Pawel Bokota wrote:
> Hi, I was thinking wh for example I can do this:
>
> 3x^4 * y^2 / 3x^2 * y = x^2 * y
>
> but can't do this:
>
> b^2 - 4ac / 4a^2 = b^2 - 1c / a
>
> ?
>
> Can someone please explain. Thank you.


--------------------
a) You can do that, why not, but it is wrong. :-)

Because (b^2 -4ac) / (4a^2) is
(b^2)/(4a^2) -(4ac)/(4a^2).

Like, (6 +3)/3 is not 6 +1 = 7.
It is (6 +3)/3 = 6/3 +3/3 = 2 +1 = 3.

--------------------------
b) You can do that, why not?

b^2 -(4ac)/(4a^2)
= b^2 -c/a

You are correct.

-----------------------------
c) But was your intention?
Was it (b^2 -4ac)/(4a^2),
or b^2 -(4ac)/(4a^2) ?



Date Subject Author
1/17/06
Read binomials fractions
Pawel Bokota
1/18/06
Read Re: binomials fractions
ticbol

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