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ticbol
Posts:
116
Registered:
1/25/05


Re: binomials fractions
Posted:
Jan 18, 2006 3:34 AM


Pawel Bokota wrote: > Hi, I was thinking wh for example I can do this: > > 3x^4 * y^2 / 3x^2 * y = x^2 * y > > but can't do this: > > b^2  4ac / 4a^2 = b^2  1c / a > > ? > > Can someone please explain. Thank you.
 a) You can do that, why not, but it is wrong. :)
Because (b^2 4ac) / (4a^2) is (b^2)/(4a^2) (4ac)/(4a^2).
Like, (6 +3)/3 is not 6 +1 = 7. It is (6 +3)/3 = 6/3 +3/3 = 2 +1 = 3.
 b) You can do that, why not?
b^2 (4ac)/(4a^2) = b^2 c/a
You are correct.
 c) But was your intention? Was it (b^2 4ac)/(4a^2), or b^2 (4ac)/(4a^2) ?



