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Topic:
Sum of primes divided by the next prime
Replies:
6
Last Post:
Aug 2, 2006 4:58 PM




Sum of primes divided by the next prime
Posted:
Aug 2, 2006 2:20 PM


Sum the primes up to p_n. Divide the sum by the next prime p_(n+1):
Sum (2+3+...+p_n)/(p_(n+1))
I found with the aid of excel two examples:
(2+3) = 0 mod 5, i.e. the next prime 5 divides the sum of all the preceding primes.
(2+3+....+61) = 0 mod 67
Below the prime 10009 there is no other cases, except those mentioned above. Are there any other p_n > 10009 ?
Tapio



