Jason Fahy
Posts:
15
From:
Edmonton, AB
Registered:
9/5/06


Re: Easy problem but my solution isn't right
Posted:
Sep 5, 2006 4:45 PM


An object is thrown upward. The height, h, is in feet. The time, t, is in second. The Formula is given by the equation: H=16T^2+96T Determine the time, if the object reach a height of 50.
50 = 16T^2 + 96T
16T^2  96T + 50 = 0
8T^2  48T + 25 = 0
Doing the quadratic formula, I get...
T = [48 +/ sqrt(2304800)]/16
T = [48 +/ 38.8]/16
T = 0.575 sec (on the way up) or T = 5.425 sec (on the way down).
In other words, I'm getting the same thing you are. Not sure where the problem is...

