
Re: can anyone tell me the answer related to aliquots
Posted:
Sep 3, 2006 12:12 PM


On Sun, 20060903 at 07:31 0700, sandeshavadhani wrote: > Robert Israel wrote: > > In article <1157270385.067754.12120@p79g2000cwp.googlegroups.com>, > > sandeshavadhani@gmail.com <sandeshavadhani@gmail.com> wrote: > > >can anyone tell me wheather 1/3+1/5+1/7+1/11+1/13+...1/n where n is > > >either prime or product of primes in the denominator of previous terms > > >in the series. Any number can be neglected.My question is wheather the > > >sum of the terms of these series can be made exactly one? > > > > Do you mean like > > 1/3 + 1/5 + 1/7 + 1/11 + 1/13 + 1/15 + 1/33 + 1/39 + 1/65 + 1/91 > > + 1/143 = 1 ?
How about 1/2 + 1/4 + 1/8 + ... = 1?
 Jeremy Boden

