
Re: number with ....
Posted:
Jan 5, 2007 6:25 AM


> Hello sir~ > > x + 6xy  y = 1. > > (x and y are positive integer). > >  > I think.... > This equation does not exist a solution. > right ? > > and then, > How can you show that this does not have a solution ? > > so, I need your advice. > >
>> Conclusion: >> the equation x + 6xy  y = a in x,y with x,y positive integer ; a given >> positive integer has an unique solution x = 1 and y = (a1)/5 iff a = 1 >> mod 5. Otherwise it has no solution.
>>Yes, nice generalization. >>Thank you very much.
there is something wrong with this generalization. e.g. x + 6 x y  y = 20 has solutions (x=3, y=1)

