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R. Brown
Posts:
54
From:
texas
Registered:
12/29/05


Re: Rbtx's Sequence Puzzle
Posted:
Mar 29, 2007 12:13 PM


It seems that the puzzle I proposed may be too simple. I would therefore like to add this 3rd and special condition:
B^{x + y + zi} = B^{x} + i(x1)
When the sequence is constructed correctly, the above eq. will always be true. where: B= related log base/ a real number
x= real number y= real number zi= pure imaginary
We can extend the above equation to read:
B^{x + y + zi} = B^{x} + i(x1)= a + bi



