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1
From:
jl
Registered:
4/25/07


Solve for X in this equation
Posted:
Apr 25, 2007 7:12 PM


I have 3 points on a circle. from those I make 2 chords. from those i make perpendicular bisecting lines. from that I find the intersection of those perpendicular bisectors. how do i set up this equation so it looks like x= ?
this is the equation i got but it doest work.
X=[((((x1x2)/(y1y2))((x1+x2)/2))((y1+y2)/2)+(((x1x3)/(y1y3))((x1+x3)/2))+((x1+x3)/2))]/[(((x1x2)/(y1y2))((x1x3)/(y1y3))] i put square brackets seperating the numerator from the denomenator



