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Topic: Solve for X in this equation
Replies: 1   Last Post: Apr 27, 2007 1:24 PM

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Posts: 1
From: jl
Registered: 4/25/07
Solve for X in this equation
Posted: Apr 25, 2007 7:12 PM
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I have 3 points on a circle. from those I make 2 chords. from those i make perpendicular bisecting lines. from that I find the intersection of those perpendicular bisectors. how do i set up this equation so it looks like x= ?


this is the equation i got but it doest work.

X=[(-(((x1-x2)/(y1-y2))((x1+x2)/2))-((y1+y2)/2)+(((x1-x3)/(y1-y3))((x1+x3)/2))+((x1+x3)/2))]/[(-((x1-x2)/(y1-y2))((x1-x3)/(y1-y3))]
i put square brackets seperating the numerator from the denomenator



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