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Topic: Volume and surface area of a sphere
Replies: 0

 Joshua Zucker Posts: 710 Registered: 12/4/04
Volume and surface area of a sphere
Posted: May 5, 1998 1:11 PM

Murray Siegel accurately points out:

One gets half the surface area 3 X^2.

Similarly, the derivative of the area of a circle with respect to
its radius is the circumference while the derivative of the area of a
square with respect to its side is only half of the perimeter.

But then inaccurately concludes:
What this
demonstrates is that the circle/sphere are more efficient than the
square/cube.

What this demonstrates is that you need to choose the right
coordinates.
This fact (derivative of volume being surface area, and derivative of
area being circumference or perimeter) results from the fundamental
theorem of calculus. It just needs the area or volume to be made from
an appropriate integral.

So the radius (or side length, or whatever) must be perpendicular to
the expanding surface of the sphere or cube.

Also it must increase in a direction such that all of the side lengths
are increased.

So for a square or cube, you need to use as the "radius" the segment
from the center perpendicular to each face, which is half as long as
the side of the square or cube.

Area of square = 4x^2
perimeter of square = 8x

Volume of cube = 8x^3
Surface area = 24x^2

works fine.

--Joshua Zucker