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Re: Question about logarithms
Posted:
Sep 6, 2007 6:32 PM
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There is, actually, a number system in which the logarithm of -8 to the base -2 comes out to be 3, and uniquely so.
That would be 3-adics. This is how it works: render the logarithm as ln(-8)/ln(-2). Translate the arguments into 3-adics; each has the form 1+y where y ends with 0. Feed these into the Maclaurin series for natural logarithms and observe that both series converge. Cancel out a common terminal zero from the natural logarithms and do the division. Voila, your quotient is ...000000010 which, in base ten, is 3.
In general, logarithms in p-adics may be defined for numbers ending with 1 in the p-adic representation (except p = 2 where you need ...01), and they have all the properties of logarithms in more conventional systems. I think it's pretty neat.
--OL
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