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RE: Exponents: getting the value of x.
Posted:
Sep 11, 2007 2:52 PM


For exponential equations such as these, you can solve for x by taking the log (common or natural) of both sides, then using a property of logarithms to get the x out of the exponent. For example:
2^x = 16
log 2^x = log 16
x log 2 = log 16
x = log 2 / log 16
If you punch this into a calculator, it gives you 4.
This same technique can be used on 2^x = 15 to get
X = log 15/ log 2
X = 3.9069 (approximately)
This of course, requires use of a calculator or log tables.
Cindy
Original Message From: numeracyapproval@world.std.com [mailto:numeracyapproval@world.std.com] On Behalf Of Ed Wall Sent: Saturday, September 08, 2007 6:48 PM To: numeracy@europe.std.com Subject: Re: Exponents: getting the value of x.
An interesting question. A comparable question, in a sense, is how do you get x in 2 times x = 8 without using a calculator. A, perhaps, more interesting question is how do you get x in
2^x = 15
without a calculator?
Ed Wall
>2^4 = 16 > >now > >2^x = 16 > >we all know that x = 4. But how exactly do we get x without using a >calculator? > > > >To unsubscribe from the Numeracy mail list send email to >majordomo@world.std.com. >In the body of the message type "unsubscribe numeracy your_address" > >If you have any questions email edl@world.std.com
 To unsubscribe from the Numeracy mail list send email to majordomo@world.std.com. In the body of the message type "unsubscribe numeracy your_address"
If you have any questions email edl@world.std.com
 To unsubscribe from the Numeracy mail list send email to majordomo@world.std.com. In the body of the message type "unsubscribe numeracy your_address"
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