The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » Math Topics » geometry.pre-college

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: analytic math/geometry
Replies: 1   Last Post: Oct 30, 2007 8:14 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]

Posts: 1
From: Md
Registered: 10/29/07
analytic math/geometry
Posted: Oct 29, 2007 11:15 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

There is a straight line which keep getting new "ends" and creating new segments. First, it has 2 then 3 ends,4, 5 6 etc. As you advance adding new ends, the number of segments icreases in a larger number than the number of ends. The first 2 is only 1 segment, when it's 3 is 3 segments, when it's 4 it's 6 segments, with 5 it's 10 segments, etc.
I figure that the first term of the conjecture is n-1 when "n" is the number of ends.
For instance:
for 2 ends: n-1 = 1
For 3 ends: (n-1) + 1 = 2 +1 = 3
for 4 ends: (n-1) + 2 + 1 = 6
for 5 ends: (n-1) + 3 + 2 + 1 = 10
and so on and so forth. Every time you increase the number of ends by one, you need to add the new number (n-1) plus the previous number of segments.
The question is to design the abbreviated form to solve just by giving the number of ends.
A second question is add all the "odd" number of ends. In this formula.
Thank you!

Math Being

Date Subject Author
Read analytic math/geometry
Read Re: analytic math/geometry

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.